Here is the problem of the day. We are going to cover some rules today. \[ \textrm{distance formula between P(x1,y1) and Q(x2, y2) is } |PQ| = \sqrt{ (x2-x1)^{2}+ (y2-y1)^{2} } \]
Calculus – Find the Domain of a function
Here is the problem of the day. \[ \textrm{Find the domain of }\textit{f(x) = } \frac{\sqrt{1-ln(x)}}{2-x^{2}} \] \[ \textrm{Answer:} \left ( 0,\sqrt{2} \right )\cup \left ( \sqrt{2},e \right ] \] The way to solve the “find the domain” problems can